embarassing request - will you be my math tutor?

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digger1
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27 Jul 2008, 1:41 am

I suck at math. You know how some people are illiterate? I'm that way with math. I don't know if it's functional or not.

I have a grasp of the basics; addition, subtraction, multiplication and division. I had an understanding of decimals but have a hard time with placements (tens, hundreds, thousands and where to put the decimal). Fractions I am very bad with and I'd really like to learn algebra.



traveller011212
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28 Jul 2008, 5:32 pm

First thing, this stuff in NOT intuitive. Practice is the only way to get better at it. buy one of those 'for dummies' books or the like and have fun.

quick lesson:

placement:

The decimal determines the tens etc. place as follows: 987,654,321.ABCDEFG (I used letters after the decimal for ease of reference).

every set of three digits is collected in the naming scheme. The first triplet is unique in that it really defined the prefixes of the other groups to the left of the decimal (and all but the first to the right). When I mention a digit or capital letter I am making reference to that particular location. The alphanumeric is just a placeholder. Now, to begin.

1 = ones place (this place in each triplet usually has no prefix. Since the 1 position has no root word
than 'ones' takes its place)
2 = Tens
3 = Hundreds

Now for the more common triplets
4 - 6 = thousands
4 = thousands
5 = ten-thousands
6 = hundred-thousands

7-9 = millions
7 = millions
8 = ten-millions
9 = hundred-millions

This would go on for the remainder of the left side digits. Practice with Billions, etc.

Now the right side:

The first triplet actually includes the decimal (well... it works to think of it that way)

A = tenth (1/10)
B = hundredth (1/100)

C - E = Thousandths
C = thousandth (1/1000)
D = ten-thousandths (1/10,000)

etc.

Put the decimal where it will make the number you want to make.

Fractions:

A/B is the fraction of A over B. It is also A divided by B. Fractions are really just a short hand for that operation. Looking at fractions that way it is simple to see that

1/3 < 2/3

because 1 divided by three is half of 2 divided by three. If ever you need to compare two fractions then just divide them out and compare the decimal forms.

0.33333 vs. 0.666667 is clear

Now for fraction operations.

Multiply (and divide):

Multiplication and division is easier to grasp with fractions because you don't first need to manipulate the fractions.

A/B*C/D = ?

5/6*8/9 = ?

Here you just multiply the numerators together to get the new numerator, and do the same with the denominator.

A/B*C/D = A*B/(C*D)

5/6*8/9 = 5*8/(6*9)

for division

(A/b)/(c/d) = ?

(5/6)/(8/9) = ?

I forget the proof, but dividing by a fraction is the same as multiplying by the reciprocal of said fraction.

(A/b)/(c/d) = A/b*c/d = (A*d)/(b*c)

(5/6)/(8/9) = 5/6*9/8 = (5*9)/(6*8)



addition (and subtraction):

A/B + C/D = ?

5/6 + 8/9 = ?

B and D need to be equal. How? see below.

multiply the first fraction (A/B) by D/D and the second fraction (C/D) by (B/B).

Quote:
[NOTE: if you have the addition of many fractions where the denominator of each respectively are B,D,F,H,I,etc. then you would multiply each fraction by each denominator over itself until all fractions have the same denominator:

A/B*(D/D*F/F*H/H*I/I) and G/H*(B/B*D/D*F/F*I/I) ]


Now we have the following

A*D/(B*D) + C*B/(B*D)

5*9/(6*9) + 8*6/(6*9)

now that we have the same denominator we can combine the two fractions

(A*D + B*C)/(B*D)

(5*9 + 8*6)/(6*9)


Fractions can be more exact because 1/3 written in decimal form in infinitely long.

1/3 = 0.33333333333333333333333333333...3333333333333...3333333...333333333...(you get the idea)


Hope that help at least a little.



traveller011212
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28 Jul 2008, 5:40 pm

Algebra:

the form is usually something like the below:

4*x + 2 = 10 what is x

what you need to do is take the operations that you know and use them to get x on one side of the equals and the numbers on the other.

one important note: x/x = 1

1) move all the terms without x to one side of the equations. Also move terms with x to the other.

4*x + 2 - 2 = 10 - 2 == 4*x = 10 - 2 = 8

2) divide out any constants to solve for x

4*x = 8 == 4*x/4 = 8/4 == x = 2

The key is adding and subtracting from both sides of the equation so that sums and differences equate to 0 (zero) and that multiplication and division equate to one (1).

another one, harder

4*x + 2 + 8*x = 38

1) 4*x + 8*x = 36

2) grouping terms here

x*(4 + 8) = 36 = x*12

36/12 = x = 3



digger1
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29 Jul 2008, 3:42 pm

huh?

all of it...huh?



twoshots
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01 Aug 2008, 11:27 pm

I could try... Any specific questions?


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