can anyone solve these problems?

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Joined: 27 May 2007
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01 Dec 2008, 10:46 pm

Got most of them right; I struggle with probabilities, but managed them. It was the year one I got wrong - forgot about leap years.

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jus4u76
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01 Dec 2008, 10:55 pm

Death_of_Pathos wrote:

So yes? No?

why don't you ask others if they're a troll. you are personist. also why converse with a person you don't like? i don't understand why you're questioning me about posting posts and if you have asperger's why are you so into socializing. leave people alone!

Death_of_Pathos
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01 Dec 2008, 11:04 pm

jus4u76 wrote:

Death_of_Pathos wrote:

So yes? No?

When you edit your posts you really should make some sort of note of it.

Personist? Urban Dictionary is the only place I could find what that meant.

In any case, I've made up my mind about your motivations and am going to be reporting you to the mods.

sbcmetroguy
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01 Dec 2008, 11:06 pm

Death_of_Pathos wrote:

In any case, I've made up my mind about your motivations and am going to be reporting you to the mods.

^^ Me too.

LostInSpace
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01 Dec 2008, 11:12 pm

Fnord wrote:

The realm of probability includes the equal possibility of either 3 yellow, 5 red, and 1 blue OR 7 blue, 5 red, and 1 yellow. Nowhere in any of the rules was the use of probability theory prohibited. Remember, the minimum number of balls was specified, not the order of the draw!

Except that it specifically states the fewest in order to ENSURE that you will get one of each. Probability doesn't "ensure" anything- it merely gives you the odds. The odds may be in favor of getting 3 different colored balls at less than 13 draws, but you cannot be sure of getting three different unless you choose 13. Think of it this way, how many balls do you have to draw so that 100% of the time you have selected all three colors?

Edited: Looks like Death of Pathos beat me to it.

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Last edited by LostInSpace on 01 Dec 2008, 11:19 pm, edited 2 times in total.

jus4u76
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01 Dec 2008, 11:12 pm

sbcmetroguy wrote:

Death_of_Pathos wrote:

In any case, I've made up my mind about your motivations and am going to be reporting you to the mods.

^^ Me too.

what's mods? i got suspended from yahoo so many times, too. wow i guess i don't even belong here.

ForsakenEagle
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02 Dec 2008, 12:14 am

Woah! These questions are going over my head right now.

I'll tag this topic so I can try again in the morning.

Mike61290
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02 Dec 2008, 1:01 am

Fnord wrote:

jus4u76 wrote:

Fnord wrote:

jus4u76 wrote:

In Aunt Lucy's garden there are about 50-100 tulips. She says that 20% of the tulips are yellow and 1/7 of them are white. How many tulips does she have? ans: 80, 75, 70 or 56

70, because this number is the only one with both 5 and 7 as factors. (20% = 1/5).

jus4u76 wrote:

There are exactly 100 sheep grazing in a field. Each of them is white or black. We know that among them there is at least one black sheep and out of any two at least one is white. How many black sheep are grazing in the field? 1,2,49 or 50

1, because any combination of two sheep must have one that is white. If there were two or more black sheep, they would form at least one combination where neither of the sheep is white.

jus4u76 wrote:

Baby Tom was born on Thursday, 24th of May, 2007. When will be his birthday on Thursday again? 2012,13,14 or 15

2012, because I used the "Adjust Date/Time" function of my toolbar clock to figure it out.

jus4u76 wrote:

You have 5 red balls, 7 blue balls and 3 yellow balls in a box. You reach in without looking and pull out one ball at a time. What is the fewest number of balls you would need to take out to be sure you took out at least one ball of each color? 3,5,9 or 13

9, because the first three balls could each be yellow, and the next 5 balls could each be red; thus, the next ball would have to be blue.

What did I win?

that's cheating 2012 and the answer is 13 balls.

There is no cheating without pre-stated rules prohibiting the use of timekeeping devices.

Please demonstrate why "13" must be the correct answer.

because if you pull out 9 balls then you could pull out 5 red balls and 4 blue balls and still not have all 3, you have to be SURE to get all 3.

A = largest
B = middle
C = smallest

the formula for any problem of this type is A + B + 1 = answer

Remember you have to be SURE with NO possibility of EVER not getting all of the colors. So what you should have done is figured out the max you could pull out without getting all the colors and then pull 1 more out to get the last color.

I have ocd family and friends, not a single one of them would ever not capitalize an i. The only reason I capitalize at all is because of their incessant nagging about it.

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IsotropicManifold
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02 Dec 2008, 3:41 am

jus4u76 wrote:

In Aunt Lucy's garden there are about 50-100 tulips. She says that 20% of the tulips are yellow and 1/7 of them are white. How many tulips does she have? ans: 80, 75, 70 or 56

Can only be 70.

1/7 of 100 is not a whole number

so there would be 10 white tulips and 14 yellow. (hence the answer is 70)

this is a trial and error question with a tiny bit of reasoning.

ephemerella
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02 Dec 2008, 6:35 am

jus4u76 wrote:

Fnord wrote:

jus4u76 wrote:

Fnord wrote:

jus4u76 wrote:

In Aunt Lucy's garden there are about 50-100 tulips. She says that 20% of the tulips are yellow and 1/7 of them are white. How many tulips does she have? ans: 80, 75, 70 or 56

70, because this number is the only one with both 5 and 7 as factors. (20% = 1/5).

jus4u76 wrote:

9, because the first three balls could each be yellow, and the next 5 balls could each be red; thus, the next ball would have to be blue.

that's cheating 2012 and the answer is 13 balls.

Please demonstrate why "13" must be the correct answer.

It says so at the site. http://www.egopont.com/math/math_key.php

You seem like a fake. You claim to be taking college math courses and getting genius level IQ scores on these online IQ tests, but you can't explain why 13 balls is the right answer. If you can't explain why 13 balls is the right answer, you're incapable of scoring so highly as you claim. If you're taking college level math classes, I bet you're not doing well in them.

Your story doesn't hang together with with what you claim to be.

PhR33kY
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02 Dec 2008, 7:24 am

jus4u76 wrote:

In Aunt Lucy's garden there are about 50-100 tulips. She says that 20% of the tulips are yellow and 1/7 of them are white. How many tulips does she have? ans: 80, 75, 70 or 56

There are exactly 100 sheep grazing in a field. Each of them is white or black. We know that among them there is at least one black sheep and out of any two at least one is white. How many black sheep are grazing in the field? 1,2,49 or 50

Baby Tom was born on Thursday, 24th of May, 2007. When will be his birthday on Thursday again? 2012,13,14 or 15

You have 5 red balls, 7 blue balls and 3 yellow balls in a box. You reach in without looking and pull out one ball at a time. What is the fewest number of balls you would need to take out to be sure you took out at least one ball of each color? 3,5,9 or 13

I don't know about the first one. Are you sure you copyed it correctly?

There is only one sheep grazing in the field.

There are two leap years at 2008 and 20012, therefore the next time the 24th of May is on a Thursday will be in 2012.

You'd have to take out 13 balls. If you take out 12, you could still possibly have 5 red balls and 7 blue balls and no yellow balls, so you'd have to have one more to guarentee that you've got one of each color.

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PhR33kY
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02 Dec 2008, 7:42 am

I worked out the date one in my head! What do I win?

I had to figure out how many days of the week are left over at the end of the year. So I just did 365/7, which isn't so bad when you know that 50x7 is 350, so that means I just had to figure out how many times 7 went into 15 (365-15). Since there is one day left over, I knew that in each year the day week is pushed forward, except on leap years so I had to find the leap years between 2007 an 2014 when it would occur without leap years. There are two leap years in that time, one in 2008 and one in 2012, so the year would be 2 years before 2012. Since his birtday is after feburary 29th, his birthday would fall on thursday that leap year.

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