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quick give me a expression

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JakobVirgil
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28 Feb 2011, 7:48 pm

quick give me a single expression were the implicit graph is
two parallel lines one that can be expressed as 3x+1 and 3x+3.
-Jake



ruveyn
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28 Feb 2011, 8:13 pm

JakobVirgil wrote:
quick give me a single expression were the implicit graph is
two parallel lines one that can be expressed as 3x+1 and 3x+3.
-Jake


dy/dx = 3

The set of solutions to this differential equation gives all the parallel lines to 3*x.

The solution to this equation is 3x + C where C is an arbitrary constatn.

ruveyn



JakobVirgil
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28 Feb 2011, 8:35 pm

ruveyn wrote:
JakobVirgil wrote:
quick give me a single expression were the implicit graph is
two parallel lines one that can be expressed as 3x+1 and 3x+3.
-Jake


dy/dx = 3

The set of solutions to this differential equation gives all the parallel lines to 3*x.

The solution to this equation is 3x + C where C is an arbitrary constatn.

ruveyn


thank you
my brain was trapped in a circle looking for a algebraic solution.
this will get me going in the right direction.
but I do need it to be only 3x+1 and 3x+3
-Jake



JakobVirgil
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28 Feb 2011, 8:37 pm

ruveyn wrote:
JakobVirgil wrote:
quick give me a single expression were the implicit graph is
two parallel lines one that can be expressed as 3x+1 and 3x+3.
-Jake


dy/dx = 3

The set of solutions to this differential equation gives all the parallel lines to 3*x.

The solution to this equation is 3x + C where C is an arbitrary constatant.

ruveyn


thank you
my brain was trapped in a circle looking for a algebraic solution.
this will get me going in the right direction.
but I do need it to be only 3x+1 and 3x+3
-Jake



Yensid
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02 Mar 2011, 6:37 pm

JakobVirgil wrote:
quick give me a single expression were the implicit graph is
two parallel lines one that can be expressed as 3x+1 and 3x+3.
-Jake


(3x+1 - y)^2 + (3x+3 - y)^2 = 0

Where ^2 means squared, and only real numbers are permitted.


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Yensid
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04 Mar 2011, 1:06 am

Oops. I meant:

(3x+1 - y)(3x+3 - y) = 0


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Brianm
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04 Mar 2011, 3:07 am

Yensid wrote:
Oops. I meant:

(3x+1 - y)(3x+3 - y) = 0


it took me a little to understand your answer. It's my fault not yours. I'm an idiot anyway. I did study this far in Mathematics, but it may be possible I didn't get the concepts totally down. I love Math though.